Update example_queries.py

example_queries.py

@@ -1,49 +1,32 @@
-small_query=""" Tables:
-        CREATE TABLE table_name_11 (date VARCHAR, away_team VARCHAR)
-
-        Question:
-        On what Date did the Away team essendon play?
-
-        Answer:"""
-long_query="""Tables:
-
+-- Create the 'employees' table with appropriate data types
 CREATE TABLE employees (
-    EMPLOYEE_ID decimal(6,0), FIRST_NAME varchar(20),
-    LAST_NAME varchar(25), EMAIL varchar(25),
-    PHONE_NUMBER varchar(20), HIRE_DATE date,
-    JOB_ID varchar(10), SALARY decimal(8,2),
-    COMMISSION_PCT decimal(2,2), MANAGER_ID decimal(6,0),
-    DEPARTMENT_ID decimal(4,0)
-)
-CREATE TABLE jobs (
-    JOB_ID varchar(10), JOB_TITLE varchar(35),
-    MIN_SALARY decimal(6,0), MAX_SALARY decimal(6,0)
-)
-CREATE TABLE locations (
-    LOCATION_ID decimal(4,0), STREET_ADDRESS varchar(40),
-    POSTAL_CODE varchar(12), CITY varchar(30),
-    STATE_PROVINCE varchar(25), COUNTRY_ID varchar(2)
-)
-CREATE TABLE countries (
-    COUNTRY_ID varchar(2),  COUNTRY_NAME varchar(40),
-    REGION_ID decimal(10,0)
-)
-CREATE TABLE job_history (
-    EMPLOYEE_ID decimal(6,0), START_DATE date,
-    END_DATE date, JOB_ID varchar(10),
-    DEPARTMENT_ID decimal(4,0)
-)
-CREATE TABLE regions (
-    REGION_ID decimal(5,0), REGION_NAME varchar(25)
-)
-CREATE TABLE departments (
-    DEPARTMENT_ID decimal(4,0), DEPARTMENT_NAME varchar(30),
-    MANAGER_ID decimal(6,0),LOCATION_ID decimal(4,0)
-)
-
-Question:
+    employee_id INT PRIMARY KEY,
+    first_name VARCHAR(20),
+    last_name VARCHAR(25),
+    email VARCHAR(25),
+    phone_number VARCHAR(20),
+    hire_date DATE,
+    job_id VARCHAR(10),
+    salary DECIMAL(8,2),
+    commission_pct DECIMAL(2,2),
+    manager_id INT,
+    department_id INT
+);
 
-For those employees who did not have any job in the past, give me the comparison about the amount of job_id over the job_id , and group by attribute job_id, and list from low to high by the JOB_ID please.
+-- Create the 'job_history' table with appropriate data types
+CREATE TABLE job_history (
+    employee_id INT,
+    start_date DATE,
+    end_date DATE,
+    job_id VARCHAR(10),
+    department_id INT,
+    PRIMARY KEY (employee_id, start_date)
+);
 
-Answer:
-"""
+-- Query to find employees without any job history and count occurrences of each job_id
+SELECT e.job_id, COUNT(e.job_id) AS job_count
+FROM employees e
+LEFT JOIN job_history jh ON e.employee_id = jh.employee_id
+WHERE jh.job_id IS NULL
+GROUP BY e.job_id
+ORDER BY e.job_id;